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Element Tower Wars Team Mode

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Element Tower Wars Team Mode

Teams: 2v2v2v2 or 4v4 (if there are 8 players)

There are two options to determine the teams.

One option is to use the game lobby, the host chooses the mode. The key issue is this will split the map popularity-wise as each option creates another entry in the popularity list. In this method, the teams are selected in the game lobby, before the actual game commences.

The other option is if there are 8 players after the lobby countdown, offer a vote of 4v4 or 2v2v2v2. Game defaults to 2v2v2v2 otherwise. in a 2v2v2v2, 4 teams will always be available. Players would click an option to join one of the 4 teams. Players can choose to play without a team-mate by joining a currently empty team. The game will start once everyone has joined a team.

Actual game play would be similar to the current tower wars with a few modifications.

---Creeps would now be sent in 2/10/20/30/60, split equally between the 2 players in the team.

---If a player has no team-mate, he plays in one area and receives all the creeps sent to that team.

---Builders will be able to blink into a team-mate's area to build for him.

---If a tower kills a creep in a team-mate's area, the bounty is split between the owner of the tower and the player the creep spawned in.

Ideas? Suggestions? Questions? Post here!

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---If a tower kills a creep in a team-mate's area, the bounty is split between the owner of the tower and the player the creep spawned in.

I see a really strong strategy being to swap mazes right at the start with your teammate so you both are always getting some income throughout a game. Might be a good one to do with a Vet teamed with a new player, so they won't get too easily overwhelmed.

Also, how would it be figured (say 4v4) if a player drops? It would be an odd amount of creeps to split among the remaining 3 people and if it ends up being 4v1, that last person is getting 4x the creeps as usual?

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Also, how would it be figured (say 4v4) if a player drops? It would be an odd amount of creeps to split among the remaining 3 people and if it ends up being 4v1, that last person is getting 4x the creeps as usual?

I wondered the same thing for 4v4 (how to split even number amongst 3 people?). Unless someone has a clever idea, I'm going to stick with 2v2v2v2 only. That way, if someone drops it is easy to redirect the creeps.

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